The answer to fill in the blank in the question above is "greater than" based on the physic of the air density. The density of air is affected by the temperature and the pressure based on the ideal gas law. A high pressure will make the air becomes denser and the bottom of swimming pool has a higher pressure than the surface<span>.</span>
- Let, the maximum height covered by projectile be
- Projectile is thrown with a velocity = v
- Angle of projection = θ
- Velocity of projectile at a height half of the maximum height covered be
______________________________
Then –
- Now, the vertical component of velocity of projectile at the height half of will be –
Therefore, the vertical component of velocity of projectile at this height will be–
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<span>The density of fissionable uranium is not high enough. Basically more neutrons are absorbed than are produced so any chain reaction dies. hope this helps</span>
Answer:
when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted
Explanation:
Let's use the constructor equation to describe the image of a concave mirror
1 / f = 1 / p + 1q
where f is the focal length, p and q the distance to the object and the image, respectively
1 /q = 1/f - 1/p
tell us that the image is between the focal and twice the focal, let's calculate the position of the image
for both ends
case 1, distance to the object p = f
1 / q = 1 / f -1 / f
1 / q = 0
q = ∞
the image is in infinity
case2, distance to object p = 2f
1 / q = 1 / f - 1 / 2f
1 / q = 1 / 2f
q = 2f
the image is twice the focal length, the object and the image are at the same point
therefore the image when the object goes from the focal length to twice the focal length the image goes from infinity to twice the focal length, this image is real and inverted
The current in the second diode is 400mA
Data;
- First Voltage = 0.75V
- Second Voltage = 0.8V
- First Current (I) = 400mA
- Second Current(I) = ?
<h3>Current In a Series</h3>
The current in the first diode is equal to 400mA. In a series circuit, the current passing the diodes are equal. This implies that the current in the series are equal.
Diodes connected in series will be the equal.
Since I1 is 400mA, I2 will be equal to 400mA
The current in the second diode is 400mA
Learn more on current in a diode here;
brainly.com/question/1455378