Answer:
Yes! Thinking about it graphically a position vs time graph models meters per second in most cases, making every point on the line have the units m/s. If we want the find the slope we are finding the change between each point and those units would change to m/s/s or m/s^2 giving us the same units for acceleration. Simply put, slope of a velocity graph gives us acceleration.
Explanation:
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
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Answer:46.5
Explanation:is the topical formula of F= 30x+15
0.4375 m/s^2
Acceleration is change in velocity over time
Change in velocity (Vf-Vi) 9.7m/s - 6.2m/s = 3.5 m/s
Time is 8 seconds
Acceleration = 3.5m/s / 8s = 0.4375 m/s^2