All categories

2 years ago

What is the mass of an electron ?

Physics

2 answers:

OLga [1]2 years ago

8 0

Electron Mass= 9.10938356 × 10-31 kilograms

Goshia [24]2 years ago

3 0

Hey!!!

your answer is.....

the mass of an electron is....

9.10938356 × 10-31kilograms

HOPEIT HELPS YOU '_'

You might be interested in

Please help!

den301095 [7]

Hello there,

It takes 300 newtons of force and a distance of 20 meters for a moving cart to come to a stop. How much kinetic energy did this cart have?

Answer: 6000

8 0

2 years ago

The sound level measured in a room by a person watching a movie on a home theater system varies from 40 dB during a quiet part t

UNO [17]

Answer:

$\alpha=-3.01dB$

Explanation:

From the question we are told that:

Sound level intensity

$\triangle I=40dB-80dB$

Generally the equation for intensity level is mathematically given by

$\alpha=10log_{10}(I/I_x)dB$

Where

I= Intensity measured

$I_x=Threshold\ of\ audibility$

$I_x= 10-12 W / m2$

$\alpha= 10 log10 \frac{I_1}{I_x} - 10 log10 \frac{}I_2{I_x}$

$\alpha= 10 log10 \frac{I_1}{I_2}$

$\alpha=10 log10\frac{40}{80}$

$\alpha=-3.01dB$

7 0

2 years ago

nevsk [136]

Answer:

true

Explanation:

<h3><em>A healthy body will keep you in shape and less risk of getting sick</em></h3>

3 0

2 years ago

"The wave" is a particular type of pulse that can

scoray [572]

Answer:

t = 36π seconds

Explanation:

For resolving this problem, we are going to consider a representative stadium of the United States. The Mercedes-Benz Stadium located in Atlanta, Georgia has an average radius of 90 m.

Then, its circumference measures:

L = 2πr

L = 2π(90)

L = 180π m

First, we estimate the wave's velocity: the average width of an person is 0.5 m, then the velocity is:

v = x/t

Where x: person's width

t: time

v = 0.5/0.1 = 5 m/s

The time required for the pulse to make one circuit around the stadium is:

t = x/v = 180π/5 = 36π seconds

4 0

2 years ago

A plastic rod has been bent into a circle of radius R = 8.00 cm. It has a charge Q1 = +2.70 pC uniformly distributed along one-q

vovikov84 [41]

Answer:

Part a)

$V = -1.52 V$

Part b)

$V = -1.16 V$

Explanation:

Part a)

Electric potential is a scalar quantity

so here we can say that total potential due to a ring on its center is given as

$V = \frac{kQ}{R}$

here we know that

$Q = Q_1 - 6Q_1$

$Q = - 5 Q_1$

$Q_1 = 2.70 pC$

now we have

$V = \frac{(9\times 10^9)(-5\times 2.70 \times 10^{-12})}{0.08}$

$V = -1.52 V$

Part b)

Potential on the axis of the ring is given as

$V = \frac{kQ}{\sqrt{r^2 + R^2}}$

$V = \frac{(9\times 10^9)(-5\times 2.70\times 10^{-12})}{\sqrt{0.08^2 + 0.0671^2}}$

$V = -1.16 V$

8 0

2 years ago