I believe that is a plant called Wisteria.
Answer:
112.2L
Explanation:
Volume (V) = 300g
Temperature (T) = 822K
Pressure (P) = 0.9atm
using the ideal gas equation;
Molar gas constant (R) =
Mole (n) = Molar mass of Mercury = 200.59g/mol
= 1.496mol
Now, the volume can be calculated;
V =
∴Volume of mercury =
If the results of the experiment on repeating are not same, it shows the results are not standard, there are some factors, which are not constant
Of course, at STP, dioxygen is a gas, but 10.0 g is still 10.0 g. We could calculate its volume at STP, which is 22.4 L × its molar quantity, approx. 8⋅L . There are 1.51×1023molecules O2 in 10.0 g O2 .
Answer:
0.16mole
Explanation:
To solve this problem, we are going to assume that the number of moles of carbon to be determined is that at STP, standard temperature and pressure.
The number of moles of a substance at STP is given as;
Number of moles =
Given volume = 3.5L
Now, insert the parameters;
Number of moles = = 0.16mole