(a) Force between the two charges
The electrostatic force between the two charges is given by:
where k is the Coulomb's constant, q1 and q2 the two charges, r their separation.
In this problem:
Substituting into the equation, we find
(b) direction of particle q2
Particle q2 wants to move in the direction of the force acting on it. The direction of the force depends on the relative sign of the two charges: like charges attract each other, opposite charges repel each other. In this case, the two charges are both positive, so they repel each other and q2 tends to move away from particle q1.
Answer:
Explanation:
Givens
vi = 10 m/s
a = 1.5 m/s^2
d = 600 m
vf = ?
Formula
vf^2 = vi^2 + 2*a*d
Solution
vf^2 = 10^2 + 2*1.5 * 600
vf^2 = 100 + 1800
vf^2 = 1900
sqrt(vf^2) = sqrt(1900)
vf = 43.59 m/s
The X and Y components of the force are 90.63 Newton and 42.26 Newton respectively.
<u>Given the following data:</u>
- Angle of inclination = 25°
To determine the X and Y components of the force:
<h3>The horizontal component (X) of a force:</h3>
Mathematically, the horizontal component of a force is given by this formula:
Fx = 90.63 Newton.
<h3>The vertical component (Y) of tensional force:</h3>
Mathematically, the vertical component of a force is given by this formula:
Fy = 42.26 Newton.
Read more on horizontal component here: brainly.com/question/4080400
Answer:
y^16
Explanation:
who need to add the exponents only
7 + 9 = 16
therefore, the answer is y^16