POH = - log [ OH-]
pOH = - log [ 1 x 10⁻¹²]
pOH = 12
Answer:
The pH of the solution is 11.48.
Explanation:
The reaction between NaOH and HCl is:
NaOH + HCl → H₂O + NaCl
From the reaction of 3.60x10⁻³ moles of NaOH and 5.95x10⁻⁴ moles of HCl we have that all the HCl will react and some of NaOH will be leftover:
Now, we need to find the concentration of the OH⁻ ions.
Where V is the volume of the solution = 1.00 L
Finally, we can calculate the pH of the solution as follows:
Therefore, the pH of the solution is 11.48.
I hope it helps you!
<h2>Answer:</h2>
Option D is correct. It is independent of the reaction pathway.
<h2>Explanations:</h2><h2>What is Hess's law?</h2>
Hesslaw states that the enthalpy change of a reaction does not change regardless whether the reaction takes place in a single or multiple reaction pathways.
This shows that the total entalpy change of a reaction does not depend on the reaction pathway.
Answer:
I would think C because you dont want to sell it (A), you dont want to conduct it or launch it agai, (B or D), so you would redesign it to make it better.