All categories

2 years ago

How many grams of NaOH are contained in 500 mL of a 0.80 M sodium hydroxide solution?

Chemistry

1 answer:

4vir4ik [10]2 years ago

7 0

This is molarity: moles of solute/liters of solution. (Not molality)

1. Plug in what we know:

500 mL = 0.5 L

0.80 = moles/0.5

0.80*0.5 = moles

moles = 0.4

2. NaOH is given as 40 g/mole, so calculate the grams:

0.4 * 40 = 16 grams

answer: 16 grams

You might be interested in

URGENT CHEMISTRY EXPERT!

vovangra [49]

Answer:

Part 1: 7.42 mL; Part 2: 3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ 2Cu₃(PO₄)₂(s)

Explanation:

Part 1. Volume of reactant

(a) Balanced chemical equation.

$\rm 2Na_{3}PO_{4} + 3CuCl_{2} \longrightarrow Cu_{3}(PO_{4})_{2} + 6NaCl$

(b) Moles of CuCl₂

$\text{Moles of CuCl}_{2} =\text{ 16.7 mL CuCl}_{2} \times \dfrac{\text{0.200 mmol CCl}_{2}}{\text{1 mL CuCl}_{2}} = \text{3.340 mmol CuCl}_{2}$

(c) Moles of Na₃PO₄

The molar ratio is 2 mmol Na₃PO₄:3 mmol CuCl₂

$\text{Moles of Na$_{3}$PO}_{4} = \text{3.340 mmol CuCl}_{2} \times \dfrac{\text{2 mmol Na$_{3}$PO}_{4}}{\text{3 mmol CuCl}_{2}} =\text{2.227 mmol Na$_{3}$PO}_{4}$

(d) Volume of Na₃PO₄

$V = \text{2.227 mmol Na$_{3}$PO}_{4}\times \dfrac{\text{1 mL Na$_{3}$PO}_{4}}{\text{0.300 mmol Na$_{3}$PO}_{4}} = \text{7.42 mL Na$_{3}$PO}_{4} \\\\\text{The reaction requires $\large \boxed{\textbf{7.42 mL Na$_{3}$PO}_{4}}$}$

Part 2. Net ionic equation

(a) Molecular equation

$\rm 2Na_{3}PO_{4}(\text{aq}) + 3CuCl_{2}(\text{aq}) \longrightarrow Cu_{3}(PO_{4})_{2}(\text{s}) + 6NaCl(\text{aq})$

(b) Ionic equation

You write molecular formulas for the solids, and you write the soluble ionic substances as ions.

According to the solubility rules, metal phosphates are insoluble.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

(c) Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

6Na⁺(aq) + 2PO₄³⁻(aq) + 3Cu²⁺(aq) + 6Cl⁻(aq) ⟶ Cu₃(PO₄)₂(s) + 6Na⁺(aq) + 6Cl⁻(aq)

The net ionic equation is

3Cu²⁺(aq) + 2PO₄³⁻(aq) ⟶ Cu₃(PO₄)₂(s)

7 0

2 years ago

Lee and some other students working with Dr. Yung were conducting an experiment and ended up with some confusing results. In the

Alinara [238K]

Answer:

chung long

Explanation:

cause 3 plus 2 =9

6 0

2 years ago

Read 2 more answers

What is the concentration of the murexide soution with a transmittance of 28.65%. (molar absorptivity = 3847)

Ainat [17]

Answer:

The concentration of the murexide solution is 0.0000745 M

Explanation:

From Beer-Lambert's law,

A = εlc

A = Absorbance = 28.65% = 0.2865

ε = molar absorptivity = 3847 M/cm

l = path length = 1cm

c = concentration in mol/L = ?

c = A/εl = 0.2865/(3847×1) = 0.0000745 mol/L

Hope this Helps!

6 0

2 years ago

Is a landslide an example of erosion or weathering

Shtirlitz [24]

Answer:

It is a example of erosion

Explanation: because pieces of rock erode making it unstable a causes a landslide

7 0

2 years ago

¿Cuál será la masa molar del agua?, si el hidrógeno tiene una masa atómica H=1.0 uma y el Oxigeno de 16 uma. * 1 punto

nataly862011 [7]

Answer:

Explanation:

Sabemos que la fórmula química del agua es H2O.

Usando la información que; H = 1, O = 16, podemos calcular la masa molar del agua de la siguiente manera

[2 (1) + 16] = 18

Por tanto, la masa molar del agua es 18

3 0

2 years ago