Answer:
a price war
Explanation:
An Oligopoly is when a small group of two or more companies dominates a market. Oligopoly firms may consent to market collusion, and create barriers to new commerce entry. If the businesses do not, they will probably be forced to lower their prices and open the market to new and smaller companies.
It is the type of competition between the company selling the similar type of product , or rival companies who tries to reduce the price of the product strategizing in a way to apprehend the wider area of the market , is known as a price war .
In the event one of the firms forming the oligopoly decides to lower prices, a price war occurs breaking the balance of the oligopoly and destabilizing the equilibrium of demand and supply in that market.
Reduction of the price of any goods or commodity is considered to be one of the best method to increase its market share ,because as soon as the price of any good decreases , the sales automatically increases , as the consumers are always in search of some discounts and good deals .
price war -
The correct answer is b hope this helps air
The question in English is "<span>Determine the mass, in kg, of a material that is contained in a volume of 18L. It is known that the material density is 0.9 g/cm 3"
Answer:
</span>
We can use a simple
equation to solve this problem. <span>
d =
m/v</span><span>
<span>Where </span>d <span>is
the density, </span>m <span>is
the mass and </span>v is the volume.
d = </span>0.9<span> g/cm³
m = ?
v = </span>18 L = 18 x 10³ cm³<span>
By applying the equation,
<span> 0.9 g/cm³ = m / </span></span>18 x 10³ cm³<span>
m = 0.9 g/cm³ x </span>18 x 10³ cm³<span>
<span>
</span>m = 16200 g
m = 16.2 kg
Hence, the mass of
18 L of material is 16.2 kg.</span>
Answer:
Explanation:
Hello.
In this case, since the normal boiling point of X is 117.80 °C, the boiling point elevation constant is 1.48 °C*kg*mol⁻¹, the mass of X is 100 g and the boiling point of the mixture of X and KBr boils at 119.3 °C, we can use the following formula:
Whereas the Van't Hoff factor of KBr is 2 as it dissociates into potassium cations and bromide ions; it means that we can compute the molality of the solution:
Next, given the mass of solventin kg (0.1 kg from 100 g), we compute the moles KBr:
Finally, considering the molar mass of KBr (119 g/mol) we compute the mass that was dissolved:
Best regards.
Mass percent is the estimation of the mass of the element in a compound in percentage form. The mass % of manganese (Mn) in potassium permanganate is 34.76 %.
<h3>What is the mass percentage?</h3>
The mass percentage is defined by dividing the mass of the element by the molecular mass of the compound followed by multiplying it by 100%. It is given as,
Mass % = (Atomic Mass of element ÷ Molecular Mass) × 100
As it is known that,
Atomic Mass of manganese = 54.94 g/mol
Molecular Mass of potassium permanganate = 158.034 g/mol
Substituting values to calculate mass % as:
% Mn = (Atomic Mass of Mn ÷ Molecular Mass of KMnO₄) × 100
= (54.94 g/mol ÷ 158.034 g/mol) × 100
= 34.76 %
Therefore, 34.76% Mn is present in KMnO₄.
Learn more about mass percentage, here:
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