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2 years ago

2. Sa epikong binasa, sinusuong at nilalabanan ni Indarapatra ang mga halimaw ,

Chemistry

1 answer:

lutik1710 [3]2 years ago

5 0

Answer:

hindi sila magkapareho

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You are given a food containing 6 g protein per serving (30g), how much of the food you needto add to 100 ml solution to make a

Bas_tet [7]

Hey there!

500 mg of protein is present in 100 mL of solvent as per the concentration 0.5 mg/mL or 500 g/mL ,

So, 250 mg (0.25 g) of serving food need to be added to 100 mL solvent in order to prepare 50 mg of protein/100 mL solution.

Dilution factor = initial amount of protein / final amount of protein

= 6 g / 0.05 g = 120

Hope this helps!

4 0

2 years ago

What causes the temperature to decrease with altitude through the mesosphere?

ololo11 [35]

The temperature decreases because there is no ozone in the mesosphere and the amount of air is decreasing.

3 0

2 years ago

Qu 4.

Anna11 [10]

Answer:

It's the second one down.

Explanation:

Gold

Mass 197

Number of Protons: 79

Number of Neutrons: 197 - 79 = 118

Number of electrons: = number of protons = 97

3 0

2 years ago

Consider the following balanced reaction. How many grams of water are required to form 75.9 g of HNO3? Assume that there is exce

Iteru [2.4K]

Answer:

10.85 g of water

Explanation:

First we write the balanced chemical equation

$3NO_{2} +H_{2}O -->2HNO_{3} +NO$

Then we calculate the number of moles of nitric acid produced

n(HNO3) = $\frac{mass}{molar mass} =\frac{75.9g}{63.02g/mol}=1.2044 mol$

According to the balanced equation, water needed in moles is always half the number of moles of HNO3 produced. So since we will produce 1.2044 mol of HNO3, we will need 0.6022 mol of water. Now to calculate what mass that is:

mass(water)=number of moles*molar mass=0.6022mol*18.02g/mol=10.85g

5 0

2 years ago

The poh of a solution is 9.32. calculate the hydrogen ion concentration of the solution.

natima [27]

PH+pOH=14
pOH=9.32
pH=14-pOH=14-9.32=4.68
pH=4.68

pH=-log[H⁺]
-pH= log[H⁺]

$[H^{+}]= 10^{-pH} = 10^{-4.68}=2.09*10^{-5}

[H^{+}] = 2.09*10^{-5}M$

4 0

2 years ago