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1 year ago

Answer this question. There are 3 answers

Mathematics

1 answer:

viva [34]1 year ago

3 0

Answer:

uh?

Step-by-step explanation:

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Djxjicjcjcicifiddiciicifididididjdjhhh

Sedbober [7]

Answer:

Step-by-step explanation:

Let the unknown number be = x

Then,

x + 16 = 34

=> x = 34 - 16

=> x = 18 (Ans)

7 0

2 years ago

Read 2 more answers

If two sides of a triangle measure 12 and 7, which cannot be the perimeter of the triangle?

ser-zykov [4K]

Hi,
Let assume x the 3th side.
x<12+7==> x<19
12<x+7==>x>5
So 5<x<19==> 5+7+12<x+7+12<19+7+12
==>24<x<38
Answer d.

8 0

2 years ago

A line passes through the point (4,7) and has a slope of -5/2.

pshichka [43]

Answer:

$y=-\frac{5}{2} x+17$

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

PLEASE HELP AND ASAP!!!! look at screenshot (10 pts)

Ne4ueva [31]

Answer:

Step-by-step explanation:

Product refers to multiplication and B is the only one the uses multiplication with 8.

4 0

2 years ago

Read 2 more answers

What is the solution to sqrt 17-x=x+3? Show your work.

snow_lady [41]

Answer:

$x=1$

Step-by-step explanation:

Remember:

$(\sqrt[n]{a})^n=a\\\\(a+b)=a^2+2ab+b^2$

Given the equation $\sqrt{17-x}=x+3$ , you need to solve for the variable "x" to find its value.

You need to square both sides of the equation:

$(\sqrt{17-x})^2=(x+3)^2$

$17-x=(x+3)^2$

Simplifying, you get:

$17-x=x^2+2(x)(3)+3^2\\\\17-x=x^2+6x+9\\\\x^2+6x+9+x-17=0\\\\x^2+7x-8=0$

Factor the quadratic equation. Find two numbers whose sum be 7 and whose product be -8. These are: -1 and 8:

$(x-1)(x+8)=0$

Then:

$x_1=1\\x_2=-8$

Let's check if the first solution is correct:

$\sqrt{17-(1)}=(1)+3$

$4=4$ (It checks)

Let's check if the second solution is correct:

$\sqrt{17-(-8)}=(-8)+3$

$5\neq-5$ (It does not checks)

Therefore, the solution is:

$x=1$

3 0

2 years ago

Answer this question. There are 3 answers​

Answer this question. There are 3 answers