Answer:
There are 3 types of bills, 4 quarters, and 5 dimes in Mrs. Short's wallet. The contains twice as many 1 bills as 5 dallor bills. The number of 20 dallors multiplied by 2 is 7 more than the total number of 1 dallor and 5 dallor combined. How mnay of each type of bill is in Mrs. Short's wallet if it contains a total of 182.50 dallors
Step-by-step explanation:
.
9 .............. 100%
x................ 15%
100x = 15 . 9
100x = 135
x = <u>135</u>
100
x = 1,35
Answer:
AY=8, XZ=20
Step-by-step explanation:
WY=WA+AY, plug in values: 14=6+AY, subtract 6 from both sides: 8=AY, AY=8cm
ZA=10cm and WY bisects XZ at A, so XA=ZA and XZ = XA+ZA = 2ZA =2*10 = 20 cm
Answer:
then he would have $56 dollars left
Y² + 16 = 212
<span>y</span>² <span>= 196 </span>
<span>y = -14 and 14</span>