Answer:
can't see anything sorry can't help
<span>Radius = 4.6 m
Time for one complete rotation t = 5.5 s.
Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
Force of the cat Fc = 6m, m being the mass.
Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116
So coefficient of static friction = 0.6116</span>
Answer:
Explanation:
According to given:
- molecular mass of glycerin,
- molecular mass of water,
- ∵Density of water is
- ∴mass of water in 316 mL,
- mass of glycerin,
- pressure of mixture,
- temperature of mixture,
<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>
<u>moles of water in the given quantity:</u>
<u>moles of glycerin in the given quantity:</u>
<u>Now the mole fraction of water:</u>
<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>