Answer:
ΔL = 3.82 10⁻⁴ m
Explanation:
This is a thermal expansion exercise
ΔL = α L₀ ΔT
ΔT = T_f - T₀
where ΔL is the change in length and ΔT is the change in temperature
Let's reduce the length to SI units
L₀ = 90.5 mm (1m / 1000 mm) = 0.0905 m
let's calculate
ΔL = 25.10⁻⁶ 0.0905 (154.6 - (14.4))
ΔL = 3.8236 10⁻⁴ m
using the criterion of three significant figures
ΔL = 3.82 10⁻⁴ m
Answer:
Air at higher altitude is under less pressure than air at lower altitude because there is less weight of air above it, so it expands (and cools), while air at lower altitude is under more pressure so it contracts (and heats up).
Explanation:
Hope that helped
W = F x D
The work you put into a machine -- the input force -- is the force you apply times the distance you apply it. The work done by the machine equals the resisting weight times the distance it moves when you perform the work.
The force that peter applies to the object of distance 40m is 75N.
<h3>HOW TO CALCULATE FORCE</h3>
The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;
Force = Work done ÷ distance
According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:
Force = 3000J ÷ 40m
Force = 75N
Therefore, the force that peter applies to the object of distance 40m is 75N.
Learn more about force at: brainly.com/question/26115859
<span>An object is located 51 millimeters from a diverging lens the object has a height og 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?</span>
