7. 1,817
6 × 6 × 52
8. 456,976,000
26 × 26 × 26 × 26 × 10 × 10 × 10
9a. 25%
50% × 50%
9b. 4%
20% × 20%
9c. 10%
50% × 20%
9d. 2.5%
5% × 50%
10. 12/216 ~ 5.556%
1/6 × 3/6 × 4/6
11. 3.125%
50% × 50% × 50% × 50% × 50%
12. 15/144 ~ 10.417%
3/12 × 5/12
13. 56.25%
93.75% × 60%
14a. 45/600 = 7.5%
9/25 × 5/24
14b. 30/600 = 5%
6/25 × 5/24
Answer:
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3
Step-by-step explanation:
From the given study,
Let A be the event that the accountant has an MBA degree
Let B be the event that the accountant has at least 5 years of professional experience.
P(A) = 0.35
= 1 - P(A)
= 1 - 0.35
= 0.65
= 0.45
P(B) = 1 -
P(B) = 1 - 0.45
P(B) = 0.55
P(A ∩ B ) = 0.75
P(A ∩ B ) = 0.75 [ 1 - P(A ∪ B) ] because =
SO;
P(A ∩ B ) = 0.75 [ 1 - P(A) - P(B) + P(A ∩ B) ]
P(A ∩ B ) = 0.75 [ 1 - 0.35 - 0.55 + P(A ∩ B) ]
P(A ∩ B ) - 0.75 P(A ∩ B) = 0.75 [1 - 0.35 -0.55 ]
0.25 P(A ∩ B) = 0.075
P(A ∩ B) =
P(A ∩ B) = 0.3
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is: P(A ∪ B ) - P(A ∩ B)
= P(A) + P(B) - 2P( A ∩ B)
= (0.35 + 0.55) - 2(0.3)
= 0.9 - 0.6
= 0.3
∴
The probability that this accountant has an MBA degree or at least five years of professional experience, but not both is 0.3
Answer:
Part A. The data distributed is symmetrical.
Part B. No, he rolled a 7 the most so, he should expect to roll a 7 before anything else.
Answer:
y = (0, 1, 32, 243, 1024, 3125)