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1 year ago

Help pleaseeeeeeee :)))))) and thank you!

Mathematics

2 answers:

Nat2105 [25]1 year ago

8 0

Answer: The answer is B 103

Step-by-step explanation:

Zolol [24]1 year ago

4 0

Answer:

103

Step-by-step explanation:

103.3's 3 is closer to 0 than 5

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Ellie drew ΔLMN, in which m∠LMN = 90°. She then drew ΔPQR, which was a dilation of ΔLMN by a scale factor of one half from the c

vaieri [72.5K]

Answer:

m∠P ≅ m∠L; this can be confirmed by translating point P to point L.

Step-by-step explanation:

Angle angle (AA) similarity postulate state that two triangles are similar if two of their corresponding angle is similar. The corresponding angle for each point of the triangles will be:

∠L=∠P

∠Q=∠M

∠N=∠R

Since the 2nd triangle made from dilation, it should maintain its orientation.

Option 1 is true, ∠P corresponds to ∠L. If you move/translate point P to point L, you can confirm it because their orientation is the same.

Option 2 is false, the triangle will be similar if ∠P=∠N but you can't confirm it with translation alone.

Option 3 and 4 definitely wrong because it speaking about length, not the angle.

6 0

2 years ago

Read 2 more answers

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$