Answer:
Style A sold 15 pairs while Style B sold 13 pairs
Step-by-step explanation:
Let the number of Style A pairs be A.
Let the number of Style B pairs be B.
The store sold 28 pairs of cross-trainer shoes for a total of $2,220 and Style A sold for $70 per pair while Style B sold for $90 per pair.
This implies 2 things:
A + B = 28 ________________ (1)
and
(70*A) + (90*B) = 2220
=> 70A + 90B = 2220 ________(2)
We now have two simultaneous equations:
A + B = 28 ________________ (1)
70A + 90B = 2220 __________(2)
From (1):
A = 28 - B ________________ (3)
Put (3) in (2):
70(28 - B) + 90B = 2220
1960 - 70B + 90B = 2220
1960 + 20B = 2220
Collecting like terms:
20B = 2220 - 1960
20B = 260
B = 260 / 20
B = 13
Therefore:
A = 28 - 13 = 15
Style A sold 15 pairs while Style B sold 13 pairs.
Here is your answer
<u>EXPLANA</u><u>TION</u>
Here, we multiply <em><u>numerator</u></em> of one fraction to the <em><u>numerator</u></em> of the other fraction and similarly the <em><u>denominators</u></em> of both fractions are multiplied.
HOPE IT IS USEFUL
Answer: b > 13
Step-by-step explanation: b= 14 and 14 is larger than 13. So using the greater than symbol is correct.
Answer:
3xy + 3xz
Step-by-step explanation:
Given:
Cost = 12,050
depreciation rate = 12%
<span>
<span>
</span><span><span>
year beginning value dep.rate depreciation ending value
</span>
<span>
1
<span> 12,050.00 </span>12%
<span> 1,446.00 </span>
<span> 10,604.00
</span>
</span>
<span>
2
<span> 10,604.00 </span>12%
<span> 1,272.48 </span>
<span> 9,331.52
</span>
</span>
<span>
3
<span> 9,331.52 </span>12%
<span> 1,119.78 </span>
<span> 8,211.74
</span>
</span>
<span>
4
<span> 8,211.74 </span>12%
<span> 985.41 </span>
<span> 7,226.33
</span>
</span>
<span>
5
<span> 7,226.33 </span>12%
<span> 867.16 </span>
<span> 6,359.17
</span>
</span>
<span>
6
<span> 6,359.17 </span>12%
<span> 763.10 </span>
<span> 5,596.07
</span>
</span>
<span>
7
<span> 5,596.07 </span>12%
<span> 671.53 </span>
<span> 4,924.54
</span>
</span>
<span>
8
<span> 4,924.54 </span>12%
<span> 590.94 </span>
<span> 4,333.60
</span>
</span>
<span>
9
<span> 4,333.60 </span>12%
<span> 520.03 </span>
<span> 3,813.56
The boat will be worth $3,813.56 after 9 years.
Depreciation = beginning cost x depreciation rate
Ending cost = beginning cost - depreciation
Depreciation is the wear and tear of an object that decreases its value.</span></span></span></span>
