Answer:
The conjecture is that the unit digit of 4^n = 4 when n = odd also 4^n = 6 when n = even
Step-by-step explanation:
The conjecture is that the unit digit of 4^n = 4 when n = odd also 4^n = 6 when n = even
To prove this conjecture
unit digit = 6
hence the property is true for ; n = 1 and n = 2 and also for every odd and even number ( i.e. from 1 to 8 )
Answer:
r = - 
Step-by-step explanation:
The n th term of a GP is
= a₁ 
where a₁ is the first term and r the common ratio
Here a₁ = 18 and a₆ = - 
, then
18 
= - ( divide both sides by 18 )
= - 
( take the fifth root of both sides )
r = ![\sqrt[5]{-\frac{1}{243} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B-%5Cfrac%7B1%7D%7B243%7D%20%7D)
= -
The answer is 2x^2-3x-2.
To solve this, you take f(x)-g(x) which is 2x^2-5-3x+3. This simplifies to 2x^2-3x-2.
5x10 in expanded form is 500.
This is easy, hint, you multiply ;-;
