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1 year ago

I will give brainliest to the first to answer

Mathematics

2 answers:

bonufazy [111]1 year ago

5 0

Answer:

2/6 = 1/3

8/1 = 8

2/4 = 4/8

2/8 = 1/4

4/4 = 1

Step-by-step explanation:

2/2 = 1 and 6/2 = 3 so that would make the equivalent fraction 1/3

for 8/1 it is the same as just 8

2*2 = 4 and 4*2 = 8 so that would make the equivalent fraction 4/8

the same goes for 2/8 which is 1/4

and 4/4 is just 1

PLEASE RATE!! I hope this helps!!

If you have any questions comment below

uysha [10]1 year ago

3 0

Answer:

2/6=1/3

8/1=8

2/4=4/8

2/8=1/4

4/4=1

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Please help on this one plzzzz

deff fn [24]

We know that Angle Bisector Divides an Angle into Two Equal Angles.

As UP is the Angle Bisector of Angle U, It Divides Angle U into two Equal Parts they are Angle(1) and Angle(2)

⇒ Angle(1) = Angle(2)

Given Angle(1) = 5x + 10 and Angle(2) = 3x + 14

⇒ 5x + 10 = 3x + 14

⇒ 2x = 4

⇒ x = 2

⇒ Angle(1) = 5x + 10 = 5(2) + 10 = 10 + 10 = 20

So : Measure of Angle(1) is 20

8 0

2 years ago

Angles 1 and 2 are complementary and congruent. what is the measure of angle 1? 30° 45° 50° 75°

lesantik [10]

see the attached figure to better understand the problem

we know that

1) If angle 1 and angle 2 are complementary angles

then

m∠1+m∠2= $90\°$ ------> equation A

2) If angle 1 and angle 2 are congruent angles

then

m∠1=m∠2 ------> equation B

Substitute equation B in equation A

m∠1+(m∠1)= $90\°$

2m∠1= $90\°$

m∠1= $45\°$

therefore

<u>the answer is</u>

$45\°$

8 0

2 years ago

Read 2 more answers

Please look at picture attached! i will mark you brainlyest if right!

katrin2010 [14]

Amp is the number in front of sine so its 1/2 aka D :)

8 0

1 year ago

Shirts are on sale for 25% of the original price of $45 what is the sale price

OverLord2011 [107]

Answer: Sale price is $11.25

Explanation:

0.25 x 45=11.25

5 0

2 years ago

Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.

finlep [7]

Answer:

a) $v = \frac{[L]}{[T]} = LT^{-1}$

b) $a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

c) $\int v dt = s(t) = [L]=L$

d) $\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

e) $\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

$v = \frac{ds}{dt}$

$a= \frac{dv}{dt}$

Part a

If we do the dimensional analysis for v we got:

$v = \frac{[L]}{[T]} = LT^{-1}$

Part b

For the acceleration we can use the result obtained from part a and we got:

$a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}$

Part c

From definition if we do the integral of the velocity respect to t we got the position:

$\int v dt = s(t)$

And the dimensional analysis for the position is:

$\int v dt = s(t) = [L]=L$

Part d

The integral for the acceleration respect to the time is the velocity:

$\int a dt = v(t)$

And the dimensional analysis for the position is:

$\int a dt = v(t) = [L][T]^{-1}=LT^{-1}$

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

$\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}$

7 0

2 years ago