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1 year ago

PLS HELP WILL GIVE BRAINLIEST

Mathematics

1 answer:

Naddika [18.5K]1 year ago

3 0

Answer:

y = 1/2x - 1

Step-by-step explanation:

The x value is divided by 2 and then has 1 subtracted from it.

also for future posts, put the question in the title that way people know what you need and can click if they know the answer.

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Please help me solve this

OlgaM077 [116]

Answer:

645320

Step-by-step explanation:

Given: 6_5_2_

If a multiplication sign is placed between the second and third digit, and an equal sign is placed between the third and fourth digit, then

6_ × 5 = _2_

The passcode contains 6 DIFFERENT digits, so we know the missing numbers cannot be 6, 5, or 2.

So, do a trial and error session of multiplying 5 by numbers it could possibly be (60, 61, 63, 64, 67, 68, 69).

64 × 5 = 320. It is the only equation that is both correct and matches the digits given, so the missing digits are 4, 3, and 0. Barry's passcode is 645320.

4 0

2 years ago

A cylindrical swimming pool has a diameter of 20 feet and a height of 3.5 feet. How many gallons of water can the pool contain?

kvasek [131]

Answer:

The swimming pool will contain approx $8243\ gal$ of water.

Step-by-step explanation:

Given the swimming pool is in a cylindrical shape.

And the dimensions are $20\ feet$ diameter with a height of $3.5\ feet.$

Also, $1\ ft^3 =7.5\ gal$

First, we will find the volume of the swimming pool.

The swimming pool is in cylindrical shape.

So, the volume would be $\pi r^2h$

The height $(h)$ is given as $3.5\ feet.$ To calculate radius $(r)$ we will divide the diameter by two.

The radius of the cylinder would be $\frac{20}{2}=10\ feet$

Plug these values in the formula we get,

$\pi r^2h\\=\pi\times 10^2\times 3.5\\=3.14\times 100\times 3.5\\=1099\ ft^3$

Now, it is given $1\ ft^3 =7.5\ gal$

So, $1099\ ft^3 =1099\times 7.5\ gal=8242.5\ gal$

The swimming pool will contain approx $8243\ gal$ of water.

6 0

2 years ago

An 18-meter-tall cylindrical tank with a 4-meter radius holds water and is half full. Find the work (in mega-joules) needed to p

Sliva [168]

Answer:

W = mgh

W = 226290 x 9.8 x 9

W = 19958778Joules

W= 19.958778MegaJoules

Step-by-step explanation:

Work to full the tank is

W = mgh.

m is the mass of the water.

But density = mass/volume, where volume is the volume of the complete the remaining half full of water to fill the cylindrical tank.

mass = density x volume.

Volume of cylinder = πr2h

Volume to fill the cylinder = (πr2h)/2.(half of total volume)

Volume = (22x4x4x9)/(7x2). Height used is 18/2 = 9m

Volume = 226.29m3.

Mass = density x volume= 1000 x 226.29 = 226290kg

Therefore, the work is

W = mgh

W = 226290 x 9.8 x 9

W = 19958778Joule = 19.958778MegaJoules

7 0

2 years ago

A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108

Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

$4x+L=108$