Given:
The given quadratic polynomial is :
To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,
Equate the polynomial with 0 to find the zeroes.
Splitting the middle term, we get
The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:
Therefore, the required polynomial is .
Answer:
division
Step-by-step explanation:
Answer:
5!*4! is equivalent to 5*(4!)^2
Step-by-step explanation:
5!*4! = 2880
5*(4!)^2 = 2880
Answer:
81
Step-by-step explanation:
13 * 6 is 78
78 + 3 is 81
~hope this helps~
the answer from, (a to e) is 10