Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
28x+-21 you simplify them first
Answer:
d one i think
hope it helps
the sum of triangle is 180 degree
(0, 3)
<span>-x + 3y=9
to figure out the y-intercept, you must put the equation into y-intercept form first: y = mx + b
</span><span>-x+3y=9
3y = x + 9
y = (x/3) + (9/3)
y = x/3 + 3
</span>
Answer:
angle y
58 + 38 + y = 180 (angle sum property)
96 + y = 180
y = 180 - 96
y = 84
angle x
x = 29 (58/2)
(angle subtended by an arc at centre is double the arc at any point on remaining part of centre)
the values of x = 29 and y = 84
