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2 years ago

Choose the ratio that you would use to convert 0.5 miles to yards. Remember that there are 1,760 yards in one mile.

2 answers:

8 0

Hello there, and thank you for posting your question here on brainly.

So, you need to find the ratio of the following to figure out which one is how to find how many yards are in half a mile.

What would you need to do to find out how? Divide it.

So you'd divide it by what? 2.

Which is the result? C. 880 yd / 1 mi

Hope this helped!! ☺♥

garri49 [273]2 years ago

8 0

the answer///////////////1760/1///////////Its C//

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A 1/17th scale model of a new hybrid car is tested in a wind tunnel at the same Reynolds number as that of the full-scale protot

Olegator [25]

Answer:

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ is approximately 0.0002

Step-by-step explanation:

The given Reynolds number of the model = The Reynolds number of the prototype

The drag coefficient of the model, $c_{m}$ = The drag coefficient of the prototype, $c_{p}$

The medium of the test for the model, $\rho_m$ = The medium of the test for the prototype, $\rho_p$

The drag force is given as follows;

$F_D = C_D \times A \times \dfrac{\rho \cdot V^2}{2}$

We have;

$L_p = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2 \times L_m$

Therefore;

$\dfrac{L_p}{L_m} = \dfrac{\rho _p}{\rho _m} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_m} \right)^2$

$\dfrac{L_p}{L_m} =\dfrac{17}{1}$

$\therefore \dfrac{L_p}{L_m} = \dfrac{17}{1} =\dfrac{\rho _p}{\rho _p} \times \left(\dfrac{V_p}{V_m} \right)^2 \times \left(\dfrac{c_p}{c_p} \right)^2 = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{17}{1} = \left(\dfrac{V_p}{V_m} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{c_p \times A_p \times \dfrac{\rho_p \cdot V_p^2}{2}}{c_m \times A_m \times \dfrac{\rho_m \cdot V_m^2}{2}} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}$

$\dfrac{A_m}{A_p} = \left( \dfrac{1}{17} \right)^2$

$\dfrac{F_p}{F_m} = \dfrac{A_p}{A_m} \times \dfrac{V_p^2}{V_m^2}= \left (\dfrac{17}{1} \right)^2 \times \left( \left\dfrac{17}{1} \right) = 17^3$

$\dfrac{F_m}{F_p} = \left( \left\dfrac{1}{17} \right)^3$ = (1/17)^3 ≈ 0.0002

The ratio of the drag coefficients $\dfrac{F_m}{F_p}$ ≈ 0.0002.

5 0

2 years ago

On average, about 240 people visit a local food pantry every day and search up groceries. On an extremely cold day, visitors to

Charra [1.4K]

The answer is 420 people

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2 years ago

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Please solve if you know no trolls please im desparate

IgorC [24]

The question isn’t equal to 90° it’s equal to 180° because the line is straight it’s not a right angle. so when u equal the whole equation to 180°, you get x=18.75. then plug in the number to find the degree of each.
so angle of department would be 139.25° and angle of gas station would be 40.75°

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2 years ago

On this map, Oxford Street is perpendicular to_______ , and Rosewood Street is perpendicular to ________. Assume that the street

melamori03 [73]

Hi there!

We are looking for perpendicular angles, which means the angle between the streets is 90 degrees. So, each time we need to find the street that intersects the given street with a 90 degree angle.

On this map, Oxford Street is perpendicular to Waterloo St., and Rosewood Street is perpendicular to Oak St..

The answers are (in correct order): Waterloo St. and Oak St..
~ Hope this helps you!

6 0

2 years ago

Macy measured the mass of a 69.3 g mouse at 70.0 g. Eli measured the mass of a 3867 kg elephant at 3900 kilograms. Macy's error

coldgirl [10]

3900 - 3867 = 33kg about the size of a little boy

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2 years ago