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2 years ago

Determine the equation of a Linear Function with a negative slope, goes through the point (0,5), and has a hole at x = -1

Mathematics

1 answer:

lesya692 [45]2 years ago

3 0

Answer:

$y=\frac{-x(x+1)}{x+1} +5$

Step-by-step explanation:

This function has a slope of -1, a hole at x = -1, and a y-intercept of 5

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In triangle KLM, if K is congruent to L, KL = 9x - 40, LM = 7x - 37, & KM = 3x + 23, find x & the measure of each angle.

timurjin [86]

This is hard to solve when we don't know the visual graph this question is trying to refer from

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2 years ago

Solve the system by the elimination method. 3x - 2y - 7 = 0 5x + y - 3 = 0 To eliminate y, the LCM is 2. Which of the following

Tresset [83]

Next time, please share your system of linear equations by typing only one equation per line:

3x - 2y - 7 = 0 5x + y - 3 = 0 NO

3x - 2y - 7 = 0
5x + y - 3 = 0 YES

Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by - 2y in the first equation:

 3x - 2y - 7 = 0
2(5x + y - 3 = 0)

Then:

3x - 2y - 7 = 0
10x +2y - 6 = 0
----------------------
13x - 13 = 0, so that x = 1. Find y by subbing 1 for x in either of the 2 given equations.

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2 years ago

Read 2 more answers

Select all expressions that are equivalent to 8(t+4)

monitta

8t+32 is one expression equivalent to that.

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3 years ago

Which answer best describes the complex zeros of the polynomial function?

marysya [2.9K]

Answer-

D. The function has one real zero and two nonreal zeros. The graph of the function intersects the x-axis at exactly one location.

Solution-

The given polynomial is,

$f(x)=x^3-x^2+6x-6$

The zeros of the polynomials are,

$\Rightarrow f(x)=0$

$\Rightarrow x^3-x^2+6x-6=0$

$\Rightarrow x^2(x-1)+6(x-1)=0$

$\Rightarrow (x^2+6)(x-1)=0$

$\Rightarrow (x^2+6)=0,(x-1)=0$

$\Rightarrow x=\sqrt{-6},\ x=1$

$\Rightarrow x=1,\ \pm \sqrt6i$

Therefore, this function has only one real zero i.e 1 and two nonreal zeros i.e ±√6i . The graph of the function intersects the x-axis at exactly one location i.e at x = 1

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2 years ago

Find x . 8 4√2 √8 16

love history [14]

Answer:

Step-by-step explanation:

$(8\sqrt{2}) ^{2} = 128 \\128 / 2 = 64\\x= \sqrt{64} = 8$

8 0

2 years ago