It’s 75.4 , I’m not sure abt those answers up there
A.T.Q,
Let, the width = x
It would be: 9/16 = 4.5/x
x = 4.5/9 * 16
x = 16/2
x = 8
So, your final answer & width would be 8 cm
Hope this helps!
The answer is the number that 't' must be in order for the equation
to be a true statement.
Here's how to find it:
Write t + 8 = 15
Then subtract 8 from each side: <em> t = 7</em>
If we assume the given segments are those from the vertices to the point of intersection of the diagonals, it seems one diagonal (SW) is 20 yards long and the other (TR) is 44 yards long. The area (A) of the kite is half the product of the diagonals:
... A = (1/2)·SW·TR = (1/2)·(20 yd)·(44 yd)
... A = 440 yd²
Each row has two more boxes than the row above. The first row has one box
The boxes in a row form an arithmetic sequence with the first term, a₁ = 1 and the common difference, d=2.
The n-th term is
The sum of n terms is
Answer:
The table will have the following:
Row Number: 1 2 3 4 5 6
Boxes in the row: 1 3 5 7 9 11
Total boxes in the display: 1 4 9 16 25 36