Answer:
0.920
Step-by-step explanation:
To calculate this, we proceed to the t-table
Using degree of freedom 5 and significance level of 0.2, the t-value is 0.920
Answer:
Step-by-step explanation:
Given that Lincoln has pennies and nickles and that his total worth is $0,
we can express his total using the inequality:
Where the sum of n and p is his total
Hence, Lincoln's situation is expressed as p+n=0
Answer:
The proof is given below.
Step-by-step explanation:
Given a parallelogram ABCD. Diagonals AC and BD intersect at E. We have to prove that AE is congruent to CE and BE is congruent to DE i.e diagonals of parallelogram bisect each other.
In ΔACD and ΔBEC
AD=BC (∵Opposite sides of parallelogram are equal)
∠DAC=∠BCE (∵Alternate angles)
∠ADC=∠CBE (∵Alternate angles)
By ASA rule, ΔACD≅ΔBEC
By CPCT(Corresponding Parts of Congruent triangles)
AE=EC and DE=EB
Hence, AE is conruent to CE and BE is congruent to DE
Answer:
x = 0
y = 1
Step-by-step explanation:
2x + 3y = 3 Multiply this equation by 3
3x + 5y = 5 Multiply this equation by 2
3(2x + 3y = 3)
6x + 9y = 9
2(3x + 5y = 5 )
6x + 10y = 10 Notice the xs are the same.
6x + 9y = 9
<u>6x + 10y =10 </u> Subtract
- y = - 1 Multiply each side by -1
y = 1
2x + 3y = 3
2x + 3*1 = 3
2x = 0
x =0
Answer:
The height of the light pole to the nearest foot is approximately 50 feet
Step-by-step explanation:
The parameters given in the question are;
The length of the cable = 63 feet
The angle of elevation of the cable to the top of the light pole = 52°
With the assumption that the light pole is perpendicular to the ground, the figure formed by the light pole, the distance of the of the cable from the base of the light pole and the length of the cable form a right triangle
The question can be answered by using trigonometric relations for the sine of the given angle as follows;
The opposite leg length of the formed right triangle = The height of the light pole
The hypotenuse length = The length of the cable = 63 feet
The angle, θ = The angle of elevation = 52°
Plugging in the values, gives;
∴ The height of the light pole = 63 feet × sin(52°) ≈ 49.645 feet
The height of the light pole to the nearest foot ≈ 50 feet.