Answer:
length = 200 m
width = 400 m
Step-by-step explanation:
Let the length of the plaing area is L and the width of the playing area is W.
Length of fencing around three sides = 2 L + W = 800
W = 800 - 2L ..... (1)
Let A is the area of playing area
A = L x W
A = L (800 - 2L)
A = 800 L - 2L²
Differentiate with respect to L.
dA/dL = 800 - 4 L
It is equal to zero for maxima and minima
800 - 4 L = 0
L = 200 m
W = 800 - 2 x 200 = 400 m
So, the area is maximum if the length is 200 m and the width is 400 m.
Answer:
-40, - 42 and -44
Step-by-step explanation:
The fastes way here is trying. Lets pick a number, intelligently, and then work on it.
We need three even integers that sum -126. These will be all negative numbers and as they are consecutive they will be very similar (for example, -33 and -35 and -37). Thus, lets start by 1/3 of -126, which is -42:
(-42)+ (-44) + (-46) = - 132, so -42 no.
Lets go a step back: -40
(-40) + (-42) + (-44) = -126
So, the integers are -40, -42 and -44
Answer:315 cm
Step-by-step explanation:
7x7
7x9.5
7x9.5
7x9.5
7x9.5
42 brotha you gotta cut down the data set until you reach the median
Answer:
40%
Step-by-step explanation:
It is 40% because 8/20 times 5 is 40/100 and that is 40%.
