The unit rate of 32 is 12
Its the second one. The inverse is the opposite of the original
Kudos to the poster on the typeset math.
With cube roots we don't have to worry that things are positive.
![\sqrt[3]{16 x^4} - \sqrt[3]{128 x} = \sqrt[3]{2^4 x^4} - \sqrt[3]{2^7 x} = \sqrt[3]{2^3 x^3 2x} - \sqrt[3]{4^3 2 x} = 2x\sqrt[3]{2x} - 4\sqrt[3]{2 x}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B16%20x%5E4%7D%20-%20%5Csqrt%5B3%5D%7B128%20x%7D%20%3D%20%20%5Csqrt%5B3%5D%7B2%5E4%20x%5E4%7D%20-%20%5Csqrt%5B3%5D%7B2%5E7%20x%7D%20%3D%20%5Csqrt%5B3%5D%7B2%5E3%20x%5E3%202x%7D%20-%20%5Csqrt%5B3%5D%7B4%5E3%202%20x%7D%20%3D%202x%5Csqrt%5B3%5D%7B2x%7D%20-%204%5Csqrt%5B3%5D%7B2%20x%7D)
![= (2x-4)\sqrt[3]{2 x}](https://tex.z-dn.net/?f=%3D%20%282x-4%29%5Csqrt%5B3%5D%7B2%20x%7D%20%20%20)
Answer:
Initial value (y-intercept) of each function.
Rate of change (slope) of each function.
Initial value to compare starting points.
Slope to compare rise or fall. (Answer)
Step-by-step explanation:
Sample Response: Linear relationships can be compared using their initial values, or y-intercepts, and their rates of change, or slopes. Initial values can tell you which relationship started with a greater value. Comparing slopes can tell you which relationship is rising or falling faster.
Therefore, I included in the response
Initial value (y-intercept) of each function.
Rate of change (slope) of each function.
Initial value to compare starting points.
Slope to compare rise or fall. (Answer)
