1 year ago

Q. If A is a square matrix such that A² = A, then write the value of 7 A −(I + A)³, where I is an identity matrix.

Mathematics

1 answer:

andriy [413]1 year ago

6 0

Answer:

7A−(I + A)³

=7A−(1³ + A³ +3.I.A² +3.1².A)

=7A−(I+ A².A+3A² +34)

= 7A-(I+A.A+3A+34) (*: A² = A)

=7A-(I+ A² +6A)

= 7A-(I+A+64)

=7A-(1+7A)

=7A-I-7A

=-1

You might be interested in

a triangle has two sides of length 6 and 1. What is the smallest possible whole-number length for the third side?

Butoxors [25]

You’d have to use the Pythagorean Thereom. a^2 + b^2 = c^2. then figure out the smallest side length from there

7 0

2 years ago

A 16-foot ladder is leaning against a wall and the bottom of the ladder is 7 feet from

barxatty [35]

Answer:

13.23 feet^2

Step-by-step explanation:

8 0

2 years ago

Trisha bought a pair of shoes for $40 and a blouse for $35. Trisha's purchases are subject to a sales tax rate of 8.75%. Includi

Margarita [4]

$40+$35=$75
75/100*8.75=6.5625
6.5625+75=81.5625
approximately equal to $81.56

5 0

3 years ago

Find the slope of a line passing through the given points. 2,5) and (4,-7) help me

LekaFEV [45]

-7 -5 / 4 -2 / -12/2

-12/2 = -6

Slope: -6x

5 = 2(-6) + b

5 = -12 + b 

-12 + 17 = 5 

Slope intercept Form: y = -6x + 17

7 0

2 years ago

How can I solve |2x - 5| = 4?

Ray Of Light [21]

well, you already know an absolute value expression has a ± siblings, so let's proceed without much fuss.

$\bf |2x-5|=4\implies \begin{cases} +(2x-5)=4\implies 2x=9\implies x=\cfrac{9}{2}\\[-0.5em] \hrulefill\\ -(2x-5)=4\implies 2x-5=-4\\[1em] 2x=1\implies x=\cfrac{1}{2} \end{cases}$

4 0

2 years ago

Q. If A is a square matrix such that A² = A, then write the value of 7 A −(I + A)³, where I is an identity matrix.​

Q. If A is a square matrix such that A² = A, then write the value of 7 A −(I + A)³, where I is an identity matrix.