9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
Answer: 
Step-by-step explanation:
The exponent 1/3 is the same thing as cube rooting the expression.
![\sqrt[3]{27\sqrt[3]{z^2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%5Csqrt%5B3%5D%7Bz%5E2%7D%20%7D)
3*
Hope it helps <3
Answer:
840
Step-by-step explanation:
(−30)(−7) − (210)(−3)
=210 − (210)(−3)
=210 − (−630)
=840
Hope this helps!
brainliest?
:)
So 29-4 =25... which is a perfect square
Answer= +/- 5
