The 90% , 99% confidence interval for the population mean is 32.145 < < 35.855 and 31.093 < < 36.907
<h3>What is Probability ?</h3>
Probability is the study of likeliness of an event to happen.
It is given that
Total Population = 50
Mean = 35
The confidence interval is given by
is the mean
z is the confidence level value
s is the standard deviation
n is the population width
(a) The 90% confidence interval for the population mean
90% = 0.05
Z = 1.64
34 1.64 * 8 / √50
34 1.855
32.145 < < 35.855
(b) The 99% confidence interval for the population mean
99% = 0.005
Z=2.57
34 2.57 * 8 / √50
34 2.907
31.093 < < 36.907
Therefore the confidence interval for population mean has been determined.
The complete question is
A simple random sample of 50 items from a population width =7 resulted in a sample mean of 35. If required, round your answers to two decimal places.
a. Provide a 90% confidence interval for the population mean
b. Provide a 99% confidence interval for the population mean
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Answer:
12
Step-by-step explanation
so what I did is I divided 15 by 5 to get 3 also 9 divided by 3 equals 3 to so you could of also done that.
then i multiplied to 4 x 3 to get the missing side length which equals 12
The value of f(a)=4-2a+6, f(a+h) is , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6.
Given a function f(x)=4-2x+6.
We are told to find out the value of f(a), f(a+h) and [f(a+h)-f(a)]/hwhere h≠0.
Function is like a relationship between two or more variables expressed in equal to form.The value which we entered in the function is known as domain and the value which we get after entering the values is known as codomain or range.
f(a)=4-2a+6 (By just putting x=a).
f(a+h)==
=4-2a-2h+6()
=4-2a-2h+6
=
[f(a+h)-f(a)]/h=[-(4-2a+6 )]/h
=
=
=6h+12a-2.
Hence the value of function f(a)=4-2a+6, f(a+h) is , [f(a+h)-f(a)]/h is 6h+12a-2 in the function f(x)=4-2x+6.
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Sh(2x) = (e^2x + e^-2x)/2
<span>Thus the integral becomes </span>
<span>Int[e^3x*(e^2x + e^-2x)/2] = Int[(e^5x + e^x)/2] </span>
<span>= e^5x/10 + e^x/2 + C
</span>=(1/10)(e^5x) + (1/2)(e^x) + C