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1 year ago

9

A bag has 16 blue marbles and 14 red marbles. John will randomly select 1 marble from the bag. What is the probability that he w

ill select a red marble? *

1 answer:

Lapatulllka [165]1 year ago

8 0

Answer:

46.66% chance of red marble

Step-by-step explanation:

Red Marbles / Total Marbles gives you the percent

14 / 30 = 46.66%

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In a recent survey, 18 people preferred milk, 29 people preferred coffee, and 13 people preferred juice as their primary drink f

xxMikexx [17]

Answer:

Probability that the person preferred milk as his or her primary drink = 0.3

Step-by-step explanation:

Given -

In a recent survey, 18 people preferred milk, 29 people preferred coffee, and 13 people preferred juice as their primary drink for breakfast .

Total no of people is = 18 + 29 + 13 = 60

If a person is selected at random ,

The probability of person preferred milk = $\frac{18}{60}$

The probability of person preferred coffee = $\frac{29}{60}$

The probability of person preferred juice = $\frac{13}{60}$

Probability that the person preferred milk as his or her primary drink =

P ( milk ) = $\mathbf{\frac{No\;of\;favourable\;outcomes}{total\;no\;of\:outcomes}}$

= $\frac{18}{60}$ = 0.3

3 0

2 years ago

Find the area of the shaded region. The gray ones with grains are the shaded regions.

Kobotan [32]

Answer:

1) 69.5

2) 678.6

Step-by-step explanation:

pi3^2=28.27*9=254.5 18*18=324-254.5=69.5

pi24^2=1809.6*.5=904.8 pi6^2=113.1*.5=56.55*4=226.2 904.8-226.2=678.6

6 0

2 years ago

Calculate the sample mean and sample variance for the following frequency distribution of heart rates for a sample of American a

spin [16.1K]

Answer:

$Mean = 68.9$

$s^2 =18.1$ --- Variance

Step-by-step explanation:

Given

$\begin{array}{cccccc}{Class} & {51-58} & {59-66} & {67-74} & {75-82} & {83-90} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

Solving (a): Calculate the mean.

The given data is a grouped data. So, first we calculate the class midpoint (x)

For 51 - 58.

$x = \frac{1}{2}(51+58) = \frac{1}{2}(109) = 54.5$

For 59 - 66

$x = \frac{1}{2}(59+66) = \frac{1}{2}(125) = 62.5$

For 67 - 74

$x = \frac{1}{2}(67+74) = \frac{1}{2}(141) = 70.5$

For 75 - 82

$x = \frac{1}{2}(75+82) = \frac{1}{2}(157) = 78.5$

For 83 - 90

$x = \frac{1}{2}(83+90) = \frac{1}{2}(173) = 86.5$

So, the table becomes:

$\begin{array}{cccccc}{x} & {54.5} & {62.5} & {70.5} & {78.5} & {86.5} \ \\ {Frequency} & {6} & {3} & {11} & {13} & {4} \ \end{array}$

The mean is then calculated as:

$Mean = \frac{\sum fx}{\sum f}$

$Mean = \frac{54.5*4+62.5*3+70.5*11+78.5*13+86.5*4}{6+3+11+13+4}$

$Mean = \frac{2547.5}{37}$

$Mean = 68.9$ -- approximated

Solving (b): The sample variance:

This is calculated as:

$s^2 =\frac{\sum (x - \overline x)^2}{\sum f - 1}$

So, we have:

$s^2 =\frac{(54.5-68.9)^2+(62.5-68.9)^2+(70.5-68.9)^2+(78.5-68.9)^2+(86.5-68.9)^2}{37 - 1}$

$s^2 =\frac{652.8}{36}$

$s^2 =18.1$ -- approximated

5 0

2 years ago

The figures are similar. Find x.

Luda [366]

Answer:x=16.5

Step-by-step explanation:

22divided by 4 is 5.5

5.5 times 3 is 16.5

4 0

2 years ago

There is an error in the diagram. Choose the statement that best describes what is wrong.

marishachu [46]

Answer:

the first one is right and other are wrong

4 0

2 years ago