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1 year ago

Find the area of the shaded figure. To do so, subtract the area of the smaller

Mathematics

1 answer:

Vikentia [17]1 year ago

3 0

Answer:

x⁴ - 8x² + 9

Step-by-step explanation:

The Area of the smallest square is A1 = x . x = x²

The Area of the second square is A2 = ( x² - 3 )(x² - 3)

A2 = x⁴ - 3x² - 3x² + 9

A2 = x⁴ - 6x² + 9

The Area of the Shaded shape is A2 - A1

x⁴ - 6x² + 9 - x²

x⁴ - 8x² + 9

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3. Mrs. Garcia's class sold bottles of lemonade for $1.36 each and Mr. Runner's class sold protein bars for $1.65 each. Together

podryga [215]

Answer:

324.6

Step-by-step explanation:

because Together, the classes sold 79 items and earned $118.17 for their school

7 0

2 years ago

Calculate the sum of the first 36 terms of the arithmetic sequence defined in which a36=14 and the common difference is d=1/8

user100 [1]

Answer:

425.25

Step-by-step explanation:

Since we are given 36th term as 14 and we know common difference is $\frac{1}{8}$ , it means that from the first term, we add $\frac{1}{8}$ to each and get 14 on the 36th term. To figure out the first term, thus, we have to subtract $\frac{1}{8}$ 35 times from 14. Let's do it to get first term:

$14-35(\frac{1}{8})=\frac{77}{8}=9.625$

The sum of arithmetic sequence formula is:

$S_{n}=\frac{n}{2}[2a+(n-1)d]$

Where,

$S_{n}$ is the sum of nth term (we want to figure this out for first 36 terms)
$a$ is the first term (we figured this out to be 9.625)
$n$ is the term number (36 for our case)
$d$ is the common difference (given as $\frac{1}{8}$ )

Substituting all the values, we get:

$S_{36}=\frac{36}{2}[2(9.625)+(36-1)(\frac{1}{8})]\\S_{36}=18[19.25+4.375]\\S_{36}=18[23.625]\\S_{36}=425.25$

First answer choice is right.

7 0

2 years ago

Read 2 more answers

Shureka Washburn has scores of 67, 78, 66, and 93 on her

vichka [17]

The answer would be A

5 0

1 year ago

Can someone please help? I need by 2:45 PM

Dafna1 [17]

Answer:

dilated coordinates are A(-18,-3) and B(-6,-12)

Step-by-step explanation:

distance of new segment is 15 units

distance formula = $\sqrt){y-y_{1})^{2} +( x - x_{1})^{2} }$

5 0

2 years ago

the area of a rectangle garden is 38 1/4 square meters.The width of the garden is 4 1/2 meters.Find the length of the garden.

never [62]

Area = 38 1/4 = 153/4

Width = 4 1/2 = 9/2

Area = Length x Width

Length = Area/Width

So divide both of them:
$\sf{ \frac{153}{4} \div \frac{9}{2} =\sf{ \frac{153}{4} \times \frac{2}{9} = \frac{9 \times 17}{2\times 2}\times \frac{2}{9} = \frac{17}{2}$

So the length is equal to $\boxed{\sf{\frac{17}{2}}}$

4 0

2 years ago