The product of 3p and q-3 would be put in to equation form like this: 3p(q-3)
To find your answer. You have to distribute the 3p to by individually multiplying it by q and -3
It should now look like this:
So your answer is:
Too bad you haven't shared illustrations of the possible solutions.
Starting with 4|x+3|>8, div. both sides by 4: <span>|x+3|>2
Case 1: x+3 is already positive: then x+3>2, or x > -1
Case 2: x+3 is negative: Then -(x+3)>2, or -x - 3 > 2, or -5>x or x<-5
Draw a number line representing x values. Place empty circles at x = -5 and x = -1. Draw a vector from the circle at x = -1, to the right of x = -1. Draw a vector from the circle at x = - 5, to the left of x = -5. Note that x values between x = -5 and x = -1 are not solutions.</span>
Add the 5 amounts:
-10 + -23 = -33
-33 + 8 + 7 + 3 = -15 cents
now divide by the number of changes (5)
-15 / 5 = -3 cents
the mean change is -3 cents