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1 year ago

Match the scientist with their achievement:

Chemistry

1 answer:

Tju [1.3M]1 year ago

5 0

Answer:

Frederich Miescher- first person to isolate DNA and RNA

Frederick Griffith- first to demonstrate horizontal transmission of dna using bacteria

Gregor Mendel- documented and demonstrated inheritance patterns

Thomas Hunt Morgan- identified chromosomes as the structures responsible for inheritance

Joachim Hammerling- demonstrated that the hereditary information of of eukaryotes is contained within the nucleus

Alfred Hershey and Martha Chase- demonstrated that dna not protein was the molecule responsible for hereditary

George Beadle and Edward Tatum- used mutants to show the relationship between DNA and proteins

Albrecht Kossel- characterized the structure of adenine, guanine, cytosine, thymine, and uracil

Explanation:

Hope this helps! Pls give brainliest!

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Answer : The number of moles present in ammonia is, 70.459 moles.

Solution : Given,

Mass of ammonia = $1.2\times 10^3g$

Molar mass of ammonia = 17.031 g/mole

Formula used :

$\text{Moles of }NH_3=\frac{\text{ given mass of }NH_3}{\text{ molar mass of }NH_3}$

$\text{Moles of }NH_3=\frac{1.2\times 10^3g}{17.031g/mole}=70.459moles$

Therefore, the number of moles present in ammonia is, 70.459 moles.

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2 years ago

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What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm

Mars2501 [29]

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

$\frac{.004}{.225}=.0177777778$

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error

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2 years ago

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Report the number 315.05 to 3 significant figures.

emmainna [20.7K]

Answer:

315.

Explanation:

Hello.

In this case, since the given number has five significant figures as the zero is to the right of the first nonzero digit (3), if it is required to report it with three significant figures, it is necessary to "cut" it at the first five without any rounding since the subsequent zero is less than five.

Thus the number turns out:

315

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