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2 years ago

R is the midpoint of PQ. PR = 6x + 7 and RQ = 3x + 8, find the length of PQ.

Mathematics

1 answer:

Ksivusya [100]2 years ago

6 0

Answer:

PQ = 18

Step-by-step explanation:

If R is the midpoint of PQ, then PR = RQ

⇒ 6x + 7 = 3x + 8

⇒ 3x = 1

⇒ x = 1/3

So PR = 6x + 7 = 6(1/3) + 7 = 9

and RQ = 3x + 8 = 3(1/3) + 8 = 9

⇒ PQ = PR + RQ = 9 + 9 = 18

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mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

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In addition, we can simplify the function by algebra properties:

$\frac{x}{x^{2}+ x} = \frac{x}{x\cdot (x + 1)} = \frac{1}{x + 1}$

$g(x) = \frac{1}{x + 1}$

The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

To learn more on lateral limits: brainly.com/question/21783151

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