To solve, it would be 6.25n. That eliminates both 6n25 over P, P equals 6.25 over n, and n=6.25P, leaving P=6.25n as the answer.
Classic Algebra and its unnecessarily complicated sentence structure. As you may have probably known, Algebra has its own "vocabulary set".
"the length of a rectangle exceeds its width by 6 inches" -> length is 6 in. longer than width -> l= w + 6
Since we're solving for the length and width, let's give them each variables.
length = l = w+6
width = w
The next bit of information is "the area is 40 square inches"
Applying the formula for the area of a rectangle we can set up:
l x w = 40
replace "l", or length, with it's alternate value.
(w+6) x w = 40
distribute
+ 6w = 40
subtract 40 from both sides
+ 6w - 40 = 0
factor
(w - 4)(w + 10) = 0
solve for w
w= 4, or -10
So great, we have 2 values; which one do we choose? Since this problem is referring to lengths and inches, we will have to choose the positive value. There is not such thing as a negative distance in the real world.
We now have half of the problem solved: width. Now we just need to find the length which we can do but substituting it back into the original alternate value of l.
l = w + 6
w=4
l = 4 + 6 = 10
The length is 10 in. and the width is 4 in. Hope this helps!
The diameter is 10 so it would be pi•radius squared 3.14•52sq or 3.14•10•2=78.54 the base of the circle is 78.54
Answer:
600
Step-by-step explanation:
Multiply 30 x 20
Answer:
Step-by-step explanation: One number is four more than the other." is represented as 'x'
"One number is four more than the other." is represented as 'x+4'
"Their sum is fourteen." is represented as 'x+(x+4)=14'
"Find both numbers."
x+(x+4)=14
x+x+4=14 (add like terms)
2x+4=14 (isolate your 'x' variable on one side of the equality by subtracting 4 from both sides)
2x+4-4=14-4
2x=10 (isolate your 'x' variable by dividing by 2 from both sides)
2x/2=10/2
x=5 (this is the answer to one number)
x+4=5+4=9 (plug in 5 for 'x' and this is the answer to four more than another)
Your two numbers are 5 and 9.