- - If we have a edge area of: 2m
Then we can work out to find the surface area:
= Surface area.
So we plug in and solve and we get:
Surface area=
The distance traveled by Mr.Nersin = 4 miles
The time for which Mr.Nersin rode first = 1/2 hour
The time for which Mr.Nersin rode after a short rest = 1/10 hour
Then
The total time for which Mr.Nersin rode = (1/2) + (1/10) hour
= (5 + 1)/10 hour
= 6/10 hour
= 3/5 hour
So
Average speed of Mr. Nersin = Distance traveled / Time taken
= 4/(3/5) miles/hour
= (4 * 5)/3 miles/hour
= 20/3 miles/hour
= 6 2/3 miles/hour
= 6.67 miles per hour
So the average speed at which Mr.Nersin traveled is 6 2/3 or 6.67 miles per hour.
Written in slope intercept form y=mx+b.......m is the slope.......b is the y intercept or where the line crosses the y axis
y=-2/3x - 4
Answer is (1) 160 km in 2 hours and
(2) 16 miles in 12 minutes.
Step by step.
80 km / 1 hour = x km /2 hours
Cross multiply =
x = 160
The second one requires a little more math. Because we are looking at how far in minutes, we change the rate of 80km in 1 hour to 80 km in 60 minutes.
80 km / 60 = x / 12
Cross multiply
12x = 960
Solve for x by dividing both sides by 12
X = 16
I did the math on a print screen to explain the cross multiply.