47+ 30 is 77 so def is 77 and 103 is deg. and
Let ∠RTS=∠RST = a (say)
∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.
consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
Answer:
i dont know sorry
Step-by-step explanation:
The area of a kite:
A = d1 * d2 / 2
d1 = BD = 8 units
48 = 8 * AC / 2
48 * 2 = 8 AC
96 = 8 AC
AC = 96 : 8 = 12
Answer: D ) 12 units