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1 year ago

Find the angle in the attachment

Mathematics

1 answer:

Vadim26 [7]1 year ago

7 0

Right-angled triangle. Let x be the required angle. Tan x = 8/6. x= 53.1°

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Plz help, 15 points!

Eduardwww [97]

Answer:

$2x+3y=-6$

Step-by-step explanation:

Let the line is $y=mx+b$ where $m$ is slope and $b$ is $y-intercept$ .

The line is parallel to $2x+3y=3$ , slope of both the lines will be same.

Find the slope of $2x+3y=3$

$3y=3-2x\\y=-\frac{2}{3}x+1$

Slope of line $=-\frac{2}{3}$

$m=-\frac{2}{3}$

So the line will be $y=-\frac{2}{3}x+b$

It passes through $(3,-4)$ .

$-4=-\frac{2}{3}\times 3+b\\-4=-2+b\\b=-2\\$

Hence the line is $y=-\frac{2}{3}x-2$

$y=-\frac{2}{3}x-2\\3y=-2x-6\ \ \ \ \ \ \ (Multiply both sides by 3)\\2x+3y=-6$

6 0

2 years ago

What is the solution of (x-9)^2/3=25 algebraicallt

AnnyKZ [126]

$\bf \cfrac{(x-9)^2}{3}=25\implies (x-9)^2=75\implies \sqrt{(x-9)^2}=\sqrt{75}\implies x-9=\pm\sqrt{75} \\\\\\ x=\pm \sqrt{75}+9\implies x\approx \begin{cases} 17.66\\ -0.34 \end{cases}$

7 0

2 years ago

Perpendicular and Angle bisectors

Stels [109]

The answer is 8, because CA and BC are equal

3 0

2 years ago

I need help completing this problem ASAP

Evgen [1.6K]

Answer:

8 sqrt(5)

Step-by-step explanation:

sqrt(45) + sqrt(125)

Rewriting

sqrt(9*5) + sqrt( 25 *5)

we know sqrt(ab) = sqrt(a) sqrt(b)

sqrt(9) sqrt(5) + sqrt(25) sqrt(5)

3 sqrt(5)+5 sqrt(5)

Add like terms

8 sqrt(5)

5 0

2 years ago

Read 2 more answers

1. (01.02)

Anton [14]

Answer:4

Step-by-step explanation:

f(1)=6(1)+2

g(f(1))=2(8)+4/5

=20/5

6 0

1 year ago

Find the angle in the attachment​

Find the angle in the attachment