Explanation:
Since {v1,...,vp} is linearly dependent, there exist scalars a1,...,ap, with not all of them being 0 such that a1v1+a2v2+...+apvp = 0. Using the linearity of T we have that
a1*T(v1)+a2*T(v1) + ... + ap*T(vp) = T(a1v19+T(a2v2)+...+T(avp) = T(a1v1+a2v2+...+apvp) = T(0) = 0.
Since at least one ai is different from 0, we obtain a non trivial linear combination that eliminates T(v1) , ..., T(vp). That proves that {T(v1) , ..., T(vp)} is a linearly dependent set of W.
its the 3rd answer i think
Answer:
All the options are correct
"f(x)=(5x)/(x-x²)" is the one function among the following choices given in the question that <span>has a removable discontinuity. The correct option among all the options that are given in the question is the third option or option "C". It is the only function having a term cancelling out each other at the top and the bottom. </span>
Answer:
18.33333333%. Please mark as brainliest if I’m Correct. :)
Step-by-step explanation:
