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1 year ago

Can someone help me please? I’ve been trying to solve these questions all day.

Physics

1 answer:

qwelly [4]1 year ago

4 0

#16

If we put a resistor in circuit it will slow the speed of current

Let's check ohms law

$\\ \rm\Rrightarrow \dfrac{V}{I}=R$

So if resistance is more current is less

#17

Again use ohms law

$\\ \rm\Rrightarrow V=IR$

$\\ \rm\Rrightarrow V\propto I$

Voltage must be increased

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During a neap tide, which phase could the moon be in? select all that apply

snow_lady [41]

Hello,

Here is your answer:

The proper answer to this question is option B "<span>third quarter".

Here is how:

Neap tides are caused when the moon is three thirds full which causes the current to up rise therefore making a neap tide.

Your answer is B.

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2 years ago

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2 years ago

A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling

ivann1987 [24]

Answer:

42.99°

Explanation:

$F_h$ = Kinetic friction force

$F_{\theta}$ = Pulling force at angle $\theta$

$N_h$ = Weight of the box = 150 N

Kinetic friction force

$F_h=\muN_h$

Pulling force at angle $\theta$

$F_{\theta}=\muN_{\theta}$

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According to question

$\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N$

Applying Newton's second law in the vertical direction we get

$N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}$

The angle is 42.99°

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A box of mass m is suspended by two ropes from a ceiling. if the ropes make the same angle with the vertical, what is the tensio

lilavasa [31]

The tension, T, in each rope is T= mg/2Sinθ

<h3>What is tension force?</h3>

Tension refers to the pulling force in a string which acts in an opposite direction to the force pulling on it.

The tension in each of the ropes are equal since they both make the same angle with the vertical.

Assume the angle the ropes make with the vertical are both θ.

Let the tension in each be T₁ and T₂

Also, T₁ = T₂ = T

T₁Sinθ + T₂Sinθ = mg

2TSinθ = mg

T = mg/2Sinθ

Therefore, the tension, T, in each rope is T = mg/2Sinθ

Learn more about tension at: brainly.com/question/14336853

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