Given:
A line passes through (-5,-3) and perpendicular to .
To find:
The equation of the line.
Solution:
We have,
On comparing this equation with slope intercept form, i.e., , we get
It means, slope of this line is .
Product of slopes of two perpendicular lines is always -1.
Slope of required line is and it passes through the point (-5,-3). So, the equation of the line is
where, m is slope.
Therefore, the equation of required line is .
Answer:
-2y + 3 = 0
Step-by-step explanation:
x - 6y - 9 = 0
-6y - 9 = -x subtract x from both sides
6y + 9 = x divide both sides by -1
x = 8y + 6
6y + 9 = 8y + 6 replace x with 6y + 9
-2y + 9 = 6 subtract 8y from both sides
-2y + 3 = 0 subtract 6 from both sides
Answer:
Step-by-step explanation:
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