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1 year ago

6437585839765349 + 52367538546941478 ?

Mathematics

1 answer:

Harrizon [31]1 year ago

4 0

5.880512439 x 10^16

5.880512439 x 10^16Hope this helps!

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With Obesity on the rise, a Doctor wants to see if there is a linear relationship between the Age and Weight and estimating a pe

Romashka [77]

Answer:

112.569 ( D )

Step-by-step explanation:

Applying the estimated Regression Equation

y = b1X1 + b2X2 + a

b1 = ((SPX1Y)*(SSX2)-(SPX1X2)*(SPX2Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 596494.5/635355.88 = 0.93884

b2 = ((SPX2Y)*(SSX1)-(SPX1X2)*(SPX1Y)) / ((SSX1)*(SSX2)-(SPX1X2)*(SPX1X2)) = 196481.5/635355.88 = 0.30925

a = MY - b1MX1 - b2MX2 = 149.25 - (0.94*61.31) - (0.31*193.88) = 31.73252

y = 0.939X1 + 0.309X2 + 31.733

For x1 ( age ) =39, and x2(weight) =143

y = (0.93884*39) + (0.30925*143) + 31.73252= 112.569

where

Sum of X1 = 981

Sum of X2 = 3102

Sum of Y = 2388

Mean X1 = 61.3125

Mean X2 = 193.875

Mean Y = 149.25

attached is the Tabular calculation of the required values needed for estimated regression equation

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An object in the shape of a rectangular prism has a length of 5 inches, a width of 3 inches, and a height of 2 inches. The objec

belka [17]

Answer:

$4,080grams$

Step-by-step explanation:

the formula for density is:

$d=\frac{m}{V}$

where d is density, m is mass, and V is volume.

solving for m in the last equation:

$m=d*V$

so if we find the volume and multiply it by the density $d=8.3gr/cm^3$ we will get the mass of the object.

The volume of a rectangular prism is given by:

$V=l*w*h$

where $l$ is length, $w$ is width and $h$ is height:

$l=5in\\w=3in\\h=2in$

we substitute to find the volume:

$V=5in*3in*2in\\V=30in^3$

since the density has units of $cm^3$ we need the volume also in units of $cm^3$ , so we make the conversion using:

$1in^3=16.3871cm^3$

multiplying by 30:

$30in^3=491.612cm^3$

and now we find the mass with the equation:

$m=d*V$

substituting d and V:

$m=(8.3gr/cm^3)(491.612cm^2)\\m=4,080.36gr$

the nearest gram is: $4,080grams$

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