2 years ago

Solving Systems by Substitution

Mathematics

1 answer:

kenny6666 [7]2 years ago

7 0

Answer:

hope it will help you ....

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dimulka [17.4K]

Answer:

Step-by-step explanation:

n is the number of selections and k the number selected, that is

n = 5 and k = 2

note that n! = n(n - 1)(n - 2) ..... × 3 × 2 × 1, thus

$\frac{5(4)(3)(2)(1)}{2!(5-2)!}$

= $\frac{120}{2(1)3(2)(1)}$

= $\frac{120}{2(6)}$

= $\frac{120}{12}$

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Hitman42 [59]

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Step-by-step explanation:

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