Your answer is going to be Appellate jurisdiction.
Answer:
124.86 V
Explanation:
We have to first calculate the voltage drop across the copper wire. The copper wire has a length of 358 ft
1 ft = 0.3048 m
358 ft = 109.12 m
The diameter of 2 AWG copper wire (d) = 6.544 mm = 0.006544 m
The area of the wire = πd²/4 = (π × 6.544²)/4 = 33.6 mm²
Resistivity of wire (ρ) = 0.0171 Ω.mm²/m
The resistance of the wire =
The voltage drop across wire = current * resistance = 6.1 A * 0.056 ohm = 0.34 V
The voltage at end = 125.2 - 0.34 = 124.86 V
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The lines of magnetic field starts from North and terminates in the South direction outside the magnet and from South to North inside.
<u>Explanation:
</u>
The imaginary lines that are drawn to represent the direction and strength of magnetic field is known as magnetic field lines. The magnetic field direction remains "tangent to magnetic field line". These magnetic field lines never intersect (the magnetic field is distinctive at any point).
The density of the lines decreases when they travel from higher permeability area to lower permeability area. All the field lines have same strength. They are closed lines i.e. they always form the closed loops. By this, we can represent that the field flows from North to South Pole from outward.
Answer:
a) width=1.20m
b) The speed of the model will be 0.193m/s
Explanation:
Using Y(t)=-gt^2+Voy+ yo
g=9.8m/s
Vo=0 at t=0
Vox=1.93m/s
yo= 3.05m
Y(t) = (-1/2) 9.8t^2+3.05
Y(t) = -4.9 +3.05
0= -4.9t^2 + 3.05
t= sqrt(3.05/4.9)
t= 0.62second
Xmax= Voxt= 1.93×0.62=1.20m
b) The model is 1/12
Therefore velocity of model = 1/2×1.2×1.93
=0.193m/s