The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
_____
For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:(6,-1)
Explanation:The slope of the line can be calculated using the following formula:
slope =
We are given that:slope = -0.75
point (x1,y1) is (-2,5)
We will use each of the given points to calculate the corresponding slope, then compare the calculated slope with the given one.
For point (6,-1):slope =
= -0.75 ........> accepted choice
For point (2,8):slope =
= 0.75 ........> rejected choice
For point (-5,1):slope =
= 4/3 ........> rejected choice
For point (1,1):slope =
= -4/3 ........> rejected choice
Therefore, the first option is the only correct one.
Hope this helps :)
Answer:
Step-by-step explanation:
=
12
x
3
−
40
x
2
+
42
x
−
20 Is your answer
Answer:When two lines intersect they form two pairs of opposite angles, A + C and B + D. Another word for opposite angles are vertical angles. Vertical angles are always congruent, which means that they are equal. Adjacent angles are angles that come out of the same vertex.
here you go
Answer:
300
Step-by-step explanation:
10 x 30= 300