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2 years ago

the souder family went on a vacation with 3000$ if they spent 200 each day,how much money they got left after x days.

Mathematics

1 answer:

Alex787 [66]2 years ago

6 0

after x days they will have 3000 - 200x

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For every 15 campers at a summer camp there is 1 counselor.

katovenus [111]

Answer:

That would mean for every 30 campers there are 2 counselors and 45:3,60:4 and so on

Step-by-step explanation:

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2 years ago

I need help on this question plz

dmitriy555 [2]

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2 years ago

Read 2 more answers

while shopping for clothes, Tracey spent 38$ less than 3 times what Daniel spent. write and solve an equation to find how much D

alexandr1967 [171]

$\bold{\huge{\orange{\underline{Solution}}}}$

$\bold{\underline{ Given :- }}$

While shopping for clothes Tracey spent 38$ less than 3 times of what Daniel spent

$\bold{\underline{ To\: Find :- }}$

We have to determine the total cost spent by daniel

$\bold{\underline{ Let's \: Begin :- }}$

Cost spent by Tracey for her clothes = 38$

Let assume the spending by Daniel is x

$\bold{\underline{Therefore ,}}$

$\sf{ x / 3 = 38 }$

$\sf{ x = 38 × 3 }$

$\sf{ x = 114 dollar }$

$\sf{\red{ Hence,\: Daniel\: spent\: 114 \: dollars\: on \: His\: clothes }}$

7 0

2 years ago

4 - 5/2 * (1/10x) = 1 what is the value of x

Inga [223]

$4 - 5 / 2 * (1/10x) = 1\\$

The first step is to identify the order in which the equation must be solved, by following PEMDAS (you might know it as BEDMAS):

Parenthesis (or Brackets)

Exponents

Multiplication and Division

Addition and Subtraction

My advice would be to add parenthesis, following these rules, if you are not very good at finding them immediately by sight.

So:

$4 - 5 / 2 * (\frac{1}{10x}) = 1\\\\4 - [(5/2)*(\frac{1}{10x})]=1\\\\4-(2.5*\frac{1}{10x})=1\\\\4-\frac{2.5}{10x}-1=0\\3-\frac{x}{4}=0\\\frac{x}{4}=3\\x=3*4\\x=12$

We check our answer:

$x=12\\4 - [(5 / 2) * (1/10)*(x)] = 1\\4 - [(5 / 2) * (\frac{1}{10}) * (12))] = 1\\4 - [2.5 * (\frac{1}{10})*12] = 1\\4 - [(\frac{2.5}{10})*12] = 1\\4 - [(\frac{1}{4})*12] = 1\\4 - 3 = 1\\1=1$

We are right!

So, $x=12$ .

6 0

2 years ago

What is the probability of getting either a sum of 5 or at least one 5 in the roll of a pair of dice?

maria [59]

In a throw of 2 fair dice, there are 6*6=36 equiprobability outcomes.

To get a sum of 5, there are 4 ways, (1,4),(2,3),(3,2),(4,1) with probability of 4/36=1/9

To get at least one 5, there are 6+6-1=11 outcomes (note (5,5) has been counted in both, so subtracted from sum). The probability is 11/36

Since the two events are mutually exclusive (once we have a five, the sum can no longer be 5), we can add the probabilities to get the probability of one event or the other.

P(sum of 5 OR at least one 5)=1/9+11/36=4/36+11/36=15/36=5/9

4 0

2 years ago