Help math math ASAP please

Mathematics

1 answer:

Levart [38]1 year ago

8 0

Answe is B

Step-by-step explanation:

because if you Measured the line with the Graph it wont combine together

You might be interested in

ASAP math help algebra plzzz

skelet666 [1.2K]

This is a geometric sequence because each term is a constant multiple, called the common ratio, of the previous term. In this case the common ratio, noted as "r", is:

8/-2=-32/8=128/-32=r=-4

The first term is -2

Any geometric sequence can be expressed as:

a(n)=ar^(n-1), a=initial term, r=common ratio, n=term number.

Since we know r and a for this problem already we can say:

a(n)=-2(-4)^(n-1)

6 0

2 years ago

A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

2 years ago

Describe the correlation of the scatterplot.

pickupchik [31]

Negative correlation

3 0

2 years ago

Read 2 more answers

20 POINTS AND BRAINLIEST!! Write an exponential function in the form y=ab^x

Rudik [331]

Answer:

$y=13(4)^x$