Answer:
5, 10, 15, 20, 25, 30, 35, 40, 45, 50, ... 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ... 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, ...
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Answer:
Step-by-step explanation:
Equation:1
Equation:2
Solving Equation:1
Subtracting 'y' from both the sides:
Putting 'x' in Equation :2
Adding '4' both the sides
Putting the value of 'y' in equation:1
The solution is:
I believe the answer would be 4!
So 4 * 3 * 2 * 1
24.
Here's proof :
ABCD
ABDC
ACBD
ACDB
ADBC
ADCB
BACD
BADC
BCAD
BCDA
BDAC
BDCA
Following this order, each letter has 6 additional options, so 4! Would answer this appropriately. Some would say 6*4 but that's the same as 4*3*2 (3 and 2 becomes 6)
Answer:
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Step-by-step explanation:
Answer:
11. 78
12. 4x² - 3x - 1
Step-by-step explanation:
11. Sum of n whole numbers = ½(n² + n)
Multiply
½*n² + ½*n
= n²/2 + n/2
To find the sum of the first 12 whole number, substitute 12 for n into the equation.
= 12²/2 + 12/2
= 144/2 + 12/2
= 72 + 6
= 78
12. Area of trapezoid = ½(a + b)*h
Where,
a = 5x - 4
b = 3x + 2
h = x + 1
Area = ½(5x - 4 + 3x + 2)*(x + 1)
Area = ½(8x - 2)*(x + 1)
Area = ½[8x(x + 1) -2(x + 1)]
= ½[8x² + 8x - 2x - 2]
Add like terms
= ½(8x² - 6x - 2)
= ½(8x²) - ½(6x) - ½(2)
= 4x² - 3x - 1
