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The percentage shows that they were 28% more likely to come from Riverdale High school.
<h3>How to calculate the percentage?</h3>
From the information given, the percentage of those from Rockport will be:
= 25/(25 + 44) × 100.
= 25/69 × 100
= 36.23%
The percentage of those from Riverdale will be:
= 44/(25 + 44) × 100.
= 44/69 × 100
= 63.77%
Therefore, the difference will be:
= 63.77% - 36.23%
= 28% approximately.
Learn more about percentages on:
brainly.com/question/24304697
Answer:
opp/adj
havent u pay attention in ur math class?
you will have to find the opp using a^2+b^2+c^2
Step-by-step explanation:
Answer:
On day 20, they should both be on page 200
Step-by-step explanation:
I set the 2 equations up:
10d=8d+40 and then subtracted 8d from both sides
2d=40 and then divided both sides by 2
d=20
I then took 20 and multiplied it by 10 for Ashley (200) and then multiplied it by 8 for Carly (160) and added 40 (200)
Hope this helps!
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
